Question

Помогите с алгеброй!

Решите:
1) (3a - 2b)(3a+2b)-(3a-4b)²+20b².
2) (а+2)(а²+4)(а⁴+16)(а-2).

Answer 1

Объяснение:

$1)(3a - 2b)(3a + 2b) - {(3a - 4b)}^{2} + 20b {}^{2} = 9 {a}^{2} - 4b {}^{2} - (9 {a}^{2} - 24ab + 16 {b}^{2} ) + 20 {b}^{2} = 9 {a}^{2} - 9 {a}^{2} + 24ab - 16 {b}^{2} + 16 {b}^{2} = 24ab$

$2) \: (a + 2)(a {}^{2} + 4)( {a}^{4} + 16)(a - 2) = ( {a}^{2} - 4)( {a}^{2} + 4)( {a}^{4} + 16) =( {a}^{4} - 16)( {a}^{4} + 16) = {a}^{8} - 256$