Question

Решите систему уравнений: 2-3x=2(1-y) 4(x+y)=12

Answer 1

$\left \{ {{2-3x=2(1-y)} \atop {4(x+y)=12}} \right.$

$\\\left \{ {{x=\frac{2}{3}y } \atop {4(x+y)=12}} \right.$

$y=\frac{9}{5}$

$x=\frac{2}{3} *\frac{9}{5}$

$x=\frac{6}{5}$

$(x, y) =(\frac{6}{5} ,\frac{9}{5} )$

Answer 2

Ответ:

2-3x=2-2y

4x+4y=12

2y-3x=0

4x+4y=12

4y-6x=0

4x+4y=12

4y-4x-6x-4y=12

-10x=-12

10x=12

x=1,2