Question

Только быстро заранье спасибо!

Answer 1

$\frac{2}{\sqrt{11}-3 } -\frac{7}{\sqrt{11}-2 } =\sqrt{11} +3-(\sqrt{11} +2)=\sqrt{11} +3-\sqrt{11} -2=1\\\\\frac{3}{3+\sqrt{6} } +\frac{2}{2+\sqrt{6} } =3-\sqrt{6} -(2-\sqrt{6} )=3-\sqrt{6} -2+\sqrt{6} =1$

$\frac{3}{\sqrt{7} -2} -\frac{2}{\sqrt{7} +3} -2\sqrt{7} =\sqrt{7} +2-(-(\sqrt{7} -3))-2\sqrt{7} =\sqrt{7} +2+(\sqrt{7} -3)-2\sqrt{7} =\sqrt{7} +2+\sqrt{7} -3-2\sqrt{7} = -1$

$\frac{1}{3-\sqrt{5} } +\frac{1}{2-\sqrt{5} } +\frac{3\sqrt{5} }{4} = \frac{3+\sqrt{5}}{4} - (2+\sqrt{5})+\frac{3\sqrt{5}}{4} = \frac{3+\sqrt{5}}{4}-2-\sqrt{5} +\frac{3\sqrt{5} }{4} = \frac{3+\sqrt{5}}{4}-2-\frac{\sqrt{5} }{4} =\frac{3+\sqrt{5}-8-\sqrt{5} }{4} =\frac{-5}{4} =- \frac{5}{4}$