Question

1,6(x-2)+3,4=0,7(4+x)

Answer 1

$\displaystyle 1,6(x-2)+3,4=0,7(4+x)\\1,6x-3,2+3,4=2,8+0,7x\\1,6x+0,2=2,8+0,7x\\1,6x-0,7x=2,8-0,2\\0,9x=2,6\\\\x=\frac{26}{9}=2\frac{8}{9}$