• Предмет: Алгебра
  • Автор: qx0xqw
  • Вопрос задан 7 лет назад

помогите пожалуйста ​

Приложения:

Ответы

Ответ дал: Ляляляля109
1

6.36

1)

 \frac{1}{4x}  +  \frac{1}{2y}  =  \frac{y}{4xy}  +  \frac{2x}{4xy}  =  \frac{y + 2x}{4xy}

2)

 \frac{5}{3a}  -  \frac{2}{9b}  =  \frac{15b}{9ab}  -  \frac{2a}{9ab}  =  \frac{15b - 2a}{9ab}

3)

 \frac{a}{6m}  +  \frac{b}{8n}  =  \frac{4an}{24mn}  +  \frac{3bm}{24mn}  =  \frac{4an + 3bm}{24mn}

4)

 \frac{x}{12a}  -  \frac{y}{18b}  =  \frac{3bx}{36ab}  -  \frac{2ay}{36ab}  =  \frac{3bx - 2ay}{36ab}

6.37

1)

 \frac{x}{ab}  +  \frac{x}{ac}  =  \frac{xc}{abc}  +  \frac{xb}{abc}  =  \frac{xc + xb}{abc}

2)

 \frac{a}{xy}  -  \frac{b}{xz}  =  \frac{az}{xyz}  -  \frac{by}{xyz}  =  \frac{az - by}{xyz}

3)

 \frac{2m}{ax}  +  \frac{3n}{bx}  =  \frac{2bm}{abx}   +  \frac{3an}{abx}  =  \frac{2bm + 3an}{abx}

4)

 \frac{5a}{mn}  -  \frac{3b}{mp}  =  \frac{5ap}{mnp}  -  \frac{3bn}{mnp}  =  \frac{5ap - 3bn}{mnp}

6.38

1)

 \frac{2x - 3y}{x}  +  \frac{4 {x}^{2} - 5 {y}^{2}  }{xy}  =  \frac{2xy - 3 {y}^{2} }{xy}  +  \frac{4 {x}^{2} - 5 {y}^{2}  }{xy}  =  \frac{2xy - 3 {y}^{2}  + 4 {x}^{2}  - 5 {y}^{2} }{xy}  =  \frac{4 {x}^{2}  + 2xy - 8 {y}^{2} }{xy}

2)

 \frac{5 {a}^{2}  -  {b}^{2} }{ab}  -  \frac{3a - 2b}{b}  =  \frac{5 {a}^{2}  -  {b}^{2} }{ab}  -  \frac{3 {a}^{2} - 2ab }{ab}  =  \frac{5 {a}^{2} -  {b}^{2} - 3 {a}^{2}   + 2ab }{ab}  =  \frac{2 {a}^{2}  + 2ab -  {b}^{2} }{ab}

3)

 \frac{2 {b}^{2} + 3ax }{bx}  -  \frac{ab + 5bx}{ax}  =  \frac{2a {b}^{2} + 3 {a}^{2}  x}{abx}  -  \frac{a {b}^{2}  + 5 {b}^{2} x}{abx}  =  \frac{2a {b}^{2} + 3 {a}^{2}  x - a {b}^{2}  - 5 {b}^{2} x}{abx}  =  \frac{a {b}^{2}  + 3 {a}^{2} x - 5 {b}^{2} x}{abx}

4)

 \frac{3 {p}^{2}  + 5mn}{mp}  +  \frac{ {n}^{2} - 3mp }{np}  =  \frac{3  n{p}^{2} + 5m {n}^{2}  }{mnp}  +  \frac{m {n}^{2} - 3 {m}^{2} p }{mnp}  =  \frac{3n {p}^{2}  + 5m {n}^{2}  + m {n}^{2}  - 3 {m}^{2} p}{mnp}  =  \\  \\  =  \frac{3n {p}^{2}  + 6m {n}^{2} - 3 {m}^{2} p }{mnp}

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