• Предмет: Математика
  • Автор: kurbangalievaveronik
  • Вопрос задан 7 лет назад

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Надо 2 столбика
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Приложения:

Ответы

Ответ дал: nastya19022009
2

Ответ:

6 6\7

16 4\8

4

6

7 1\5

6 2\7

23 4\8

Ответ дал: Ляляляля109
0

1 \frac{1}{7}  + 5 \frac{5}{7}  =  \frac{8}{7}  +  \frac{40}{7}  =  \frac{48}{7}  = 6 \frac{6}{7}

9 \frac{3}{8}  + 7 \frac{1}{8}  =  \frac{75}{8}  +  \frac{57}{8}  =  \frac{132}{8}  = 16 \frac{1}{2}

3 \frac{1}{2}  + 1 \frac{1}{2}  =  \frac{7}{2}  +  \frac{3}{2}  =  \frac{10}{2}  = 5

4 \frac{3}{5}  + 1 \frac{2}{5}  =  \frac{23}{5}  +  \frac{7}{5}  =  \frac{30}{5}  = 6

5 \frac{3}{5}  + 1 \frac{3}{5}  =  \frac{28}{5}  +  \frac{8}{5}  =  \frac{36}{5}  = 7 \frac{1}{5}

3 \frac{3}{7}  + 2 \frac{6}{7}  =  \frac{24}{7}  +  \frac{20}{7}  =  \frac{44}{7}  = 6 \frac{2}{7}

16 \frac{3}{8}  + 7 \frac{1}{8}  =  \frac{131}{8}  +  \frac{57}{8}  =  \frac{188}{8}  = 23 \frac{1}{2}

5 \frac{3}{10}  +  \frac{11}{15}  =  \frac{53}{10}  +  \frac{11}{15}  =  \frac{159}{30}  +  \frac{22}{15}  =  \frac{181}{30}  = 6 \frac{1}{30}

9 \frac{5}{24}  +  \frac{35}{36}  =  \frac{221}{24}  +  \frac{35}{36}  =  \frac{663}{72}  +  \frac{70}{7}  =  \frac{733}{72}  = 10 \frac{13}{72}

9 \frac{1}{2}  + 3 \frac{1}{8}  =  \frac{19}{2}  +  \frac{25}{8}  =  \frac{76}{8}  +  \frac{25}{8}  =  \frac{101}{8}  = 12 \frac{5}{8}

9 \frac{9}{16}  + 2 \frac{1}{4}  =  \frac{153}{16}  +  \frac{9}{4}  =  \frac{153}{16}  +  \frac{36}{16}  =  \frac{189}{16}  = 11 \frac{13}{16}

7 \frac{1}{6}  + 2 \frac{11}{42}  =  \frac{43}{6}  +  \frac{95}{42}  =  \frac{301}{42}  +  \frac{95}{42}  =  \frac{396}{42}  = 9 \frac{3}{7}

9 \frac{2}{3}  + 1 \frac{1}{4}  =  \frac{29}{3}  +  \frac{5}{4}  =  \frac{116}{12}  +  \frac{15}{12}  =  \frac{131}{12}  = 10 \frac{11}{12}

2 \frac{7}{48}  + 11 \frac{77}{96}  =  \frac{103}{48}   +  \frac{1133}{96}  =  \frac{206}{96}  +  \frac{1133}{96}  =  \frac{1339}{96}  = 13 \frac{91}{96}

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