Question

2 вариант срочно пожалуй
ста

Answer 1

Ответ:

1

a)v^3 -27w^3 =v^3 -3^3w^3 = (v -3w)(v² +3v*w +9w²

b)(x^2+z)*(x^4-x^2z+z^2)

Объяснение:

x^6+z^3=x^3*2+z^3=(x^2)^3+z^3=(x^2+z)*((x^2)^2-x^2z+z^2=(x^2+z)*(x^4-x^2z+z^2)

2

А) = а^3 - ( 0,3b )^3 = a^3 - 0,027b^3

б)(4х+1)(16х²-4х+1)=(4х)³+1³=64х³+1

3

а и б на фотке

Answer 2

Ответ:

1.

а) u³-27w³=u³-(3w)³=(u-3w)(u²+(3w)²+u×3w)=(u-3w)(u²+3uw+9w²)

б) х⁶+z³=(x²)³+z³=(x²+z)((x²)²-x²z+z²)=(x²+z)(x⁴-x²z+z²)

2.

a) (a-0,3b)(a²+0,3ab+0,09b²)=a³-(0,3b)³=a³-0,027b³

б) (4х+1)(16х²-4х+1)=(4х)³+1³=64х³+1

3.

$\displaystyle a) \\ \frac{3a {}^{2} - 3ab + 3b {}^{2} }{a {}^{3} + {b}^{3} } = \frac{ 3(a {}^{2} - ab + b {}^{2} )}{ (a + b)(a {}^{2} - ab + b {}^{2} ) } = \frac{3}{a + b}$

$\displaystyle b) \\ \frac{1 - x {}^{3} y {}^{3} }{xyz - z} = \frac{(1 - xy)(1 + xy + x {}^{2}y {}^{2} ) }{z(xy - 1)} = \frac{ - (xy - 1)(1 + xy + x {}^{2}y {}^{2} ) }{z(xy - 1)} = \frac{ - x {}^{2} y {}^{2} - xy - 1}{z} = - \frac{1 + xy + x {}^{2}y {}^{2}}{z}$