Question

Помогите срочно пожалуйста

Answer 1

$\displaystyle 1)(\frac{3}{7}*\frac{33}{40}+\frac{5}{6}):1\frac{11}{12}=(\frac{99}{280}+\frac{5}6}):\frac{23}{12}=\frac{997}{840}*\frac{12}{23}=\frac{997}{70}*\frac{1}{23}=\frac{997}{1610}\\ \\2)(6\frac{7}{12}-3\frac{17}{36})*\frac{1}{2}-4\frac{1}{3}:\frac{13}{20}=(\frac{79}{12}-\frac{125}{36})*\frac{1}{2}-\frac{13}{3}*\frac{20}{13}=\frac{28}{9}*\frac{1}{2}-\frac{1}{3}*20=\\\\\frac{14}{9}-\frac{20}{3}=-\frac{46}{9}=-5\frac{1}{9}$