Question

(x-2)(4x+4)(2x-6)> или равно 0

Answer 1

• Ответ во вложении. Решено методом Интервалов.

Answer 2

$\displaystyle\bf\\(x-2)(4x+4)(2x-6)\geq 0\\\\(x-2)\cdot 4\cdot(x+1)\cdot 2\cdot(x-3)\geq 0\\\\8(x-2)(x+1)(x-3)\geq 0 \ |:8\\\\(x-2)(x+1)(x-3)\geq 0$

Нули функции в левой части неравества :

$\displaystyle\bf\\x-2=0 \ \ \Rightarrow \ \ x_{1} =2\\\\x+1=0 \ \ \Rightarrow \ \ x_{2} =-1\\\\x-3=0 \ \ \Rightarrow \ \ x_{3} =3\\\\\\- - - - - [-1]+ + + + + [2] - - - - - [3] + + + + + \\\\ Otvet :\Big [-1 \ ; \ 2\Big] \ \cup \ \Big[3 \ ; \ +\infty\Big)$