Question

Приведите уравнение 5х(3х+7)+(4х+1)^2=-19х+63 к виду x^2+px+q=0

Answer 1

5x(3x+7)+(4x+1)^2=-19x+63
15x^2+35x+16x^2+8x+1=-19x+63
15x^2+16x^2+35x+19x+8x+1-63=0
31x^2+62x-62=0

Answer 2

x^2+2x-2=0