Question

$\left \{ {{y=-\frac{2}{11}x+ }\frac{15}{11} \atop {10x-11y=9}} \right.$

Answer 1

Ответ: x=2 ; y=1

$\left \{ {{ y = - \frac{2 }{11} x + \frac{15}{11} } \atop {10 x - 11y = 9}} \right. \\ \\ \left \{ {{y + \frac{2}{11}x = \frac{15}{11} } \atop {10x - 11y = 9}} \right. \\ \\ \left \{ {{ \frac{11y + 2x }{11} = \frac{15}{11} } \atop {10x - 11y = 9}} \right. \\ \\ \left \{ {{121y + 22x = 165 \: \: \: \: \: \: \: } \atop {10x - 11y = 9 \: \: | \times 11 }} \right.$

$\left \{ {{121y + 22x = 165} \atop {110x - 121y = 99}} \right. + \\ 132x = 264 \\ x = 2$

И вместо х поставим 2

$10x - 11y = 9 \\ 10 \times 2 - 11y = 9 \\ 20 - 11y = 9 \\ - 11y = - 11 \\ y = 1$