Question

| 12 - |12x +3|| = 1 сложное уравнение с модулем​

Answer 1

$\displaystyle |12-|12x+3||=1\\12-|12x+3|=1;12-|12x+3|=-1\\\\x_1=\frac{2}{3},x_2=-\frac{7}{6},x_3=\frac{5}{6},x_4=-\frac{4}{3}$