Question

ПОЖАЛУЙСТА!!!!! 40 БАЛООВ!!!​

Answer 1

$\displaystyle 1)\left \{ {{2(3k-d)-5=2k-3d} \atop {5-(k-2d)=4d+16}} \right.\\ \\\left \{ {{k=-\frac{1}{4}d+\frac{5}{4} } \atop {5-(k-2d)=4d+16}} \right.\\ \\5-(-\frac{1}{4}d+\frac{5}{4}-2d)=4d+16\\ \\d=-7\\ \\k=-\frac{1}{4}(-7)+\frac{5}{4}\\ \\k=3\\ (d,k)=(-7,3)$

$\displaystyle 2)\left \{ {{\frac{x-2}{4}+\frac{y-2}{4}=2 } \atop {\frac{x-2}{3}-\frac{y-2}{9}=\frac{4}{3} \\ }} \right. \\\\\left \{ {{x=12-y} \atop {\frac{x-2}{3}-\frac{y-2}{9}=\frac{4}{3} }} \right. \\\\\\\frac{12-y-2}{3}-\frac{y-2}{9}=\frac{4}{3}\\ \\y=5\\ x=12-5\\ x=7\\(x,y)=(7,5)$