Question

уравнения квадратного корня
х²+5/х-1=6/х-1​

Answer 1

$\displaystyle\bf\\\frac{x^{2}+5 }{x-1} =\frac{6}{x-1} \\\\\\\frac{x^{2}+5 }{x-1} -\frac{6}{x-1} =0\\\\\\\frac{x^{2}+5-6 }{x-1} =0\\\\\\\frac{x^{2} -1}{x-1} =0\\\\\\\frac{(x-1)(x+1)}{x-1} =0\\\\\\x+1=0\\\\\\\boxed{x=-1}$