Question

Помогите пожалуйста.​

Answer 1

$\displaystyle \left \{ {{2x^2+3x-5\leq 0} \atop {7x-1\leq 5x+3}} \right.\\ \\\left \{ {{x \in [-\frac{5}{2},1\ } \atop {x\leq 2}} \right.\\ \\x \in [-\frac{5}{2},1]$$\displaystyle -\frac{5}{2}=-2,5$