Question

помогите пожалуйста ​

Answer 1

метод подстановки:

$\displaystyle \left \{ {{2x-3y=-12} \atop {x+2y=1}} \right. \\\\\left \{ {{2x-3y=-12} \atop {x=1-2y}} \right.\\ \\2(1-2y)-3y=-12\\y=2\\x=1-2*2\\x=-3\\(x,y)=(-3,2)$

Answer 2

Ответ: x=-3 ; y=2

$\left \{ {{2x - 3y = - 12 \: \: \: \: \: \: \: \: \: \: } \atop {x + 2y = 1 \: \: \: | \times - 2}} \right. \\ \\ \left \{ {{2x - 3y = - 12} \atop { - 2x - 4y = - 2}} \right. + \\ - 7y = - 14 \\ y = 2 \\ \\ x + 2y = 1 \\ x + 2 \times 2 = 1 \\ x + 4 = 1 \\ x = - 3$