Question

$0,4^{2x+1} \ \textgreater \ 0,16 \\\\3^{4x+3} \leq (\frac{1}{9} )^{x-6}$

Answer 1

0,4^(2х + 1) > 0,16
0,4^(2х + 1) > 0,4^2
2х + 1 < 2
2х < 2 - 1
2х < 1
х < 1 : 2
х < 0,5

3^(4х + 3) ≤ (1/9)^(х - 6)
3^(4х + 3) ≤ ((3^(-2))^(х - 6)
3^(4х + 3) ≤ 3^((-2)(х - 6))
3^(4х + 3) ≤ 3^(-2х + 12)
4х + 3 ≤ -2х + 12
4х + 2х ≤ 12 - 3
6х ≤ 9
х ≤ 9 : 6
х ≤ 1,5