Question

1)4÷(x-3)+2=18
2)(2x+4)(5x-4)=0
3)(x+7)(x+11)=0

Answer 1

1) 4:(х-3) +2=18, х≠3
4/х-3 + 2=18
4/х-3=18-2
4/х-3=16
4=16(х-3)
4=16х-48
-16х=-48-4
-16х=-52
х= 13/4, х≠3
х=13/4
2) (2х+4) (5х-4) =0
2х+4=0
5х-4=0
х=-2
х=4/5
3) (х+7) (х+11) =0
х+7=0
х+11=0
х=-7
х=-11