Question

1) x2 – 5x + 6 = x2 – 3x – 2x + 6 = x(x – 3) – 2(x – 3) = (x – 3)(x – 2),

2) x2 – x – 2 = x2 – 2x + x – 2 = x (x – 2) + (x – 2) = (x – 2)(x + 1),

3) x2 – 2x – 3 = x2 – 3x + x – 3 = x (x – 3) + (x – 3) = (x – 3) (x + 1).

Answer 1

Ответ:

2;0;2.

Пошаговое объяснение:

1) x2 – 5x + 6 = x2 – 3x – 2x + 6 = x(x – 3) – 2(x – 3) = (x – 3)(x – 2),

-3x+6=-3x+6=x²-5x+6=x²-5x+6;

-3x+6=x²-5x+6;

2x=x²;

X*2=x*x

x=2.

2)x2 – x – 2 = x2 – 2x + x – 2 = x (x – 2) + (x – 2) = (x – 2)(x + 1),

x-2=x-2=x²-x-2=x²-x-2;

x-2=x²-x-2;

x-2=x²-x-2;

x=x²-x;

x²=0;

x=0.

3)x2 – 2x – 3 = x2 – 3x + x – 3 = x (x – 3) + (x – 3) = (x – 3) (x + 1).

-3=-3=x²-2x-3=x²-2x-3;

-3=x²-2x-3;

0=x²-2x;

x²=2x;

x*x=2*x;

x=2