Question

(2ctg270°−2cos60°+sin^2 60°)^−1

Answer 1

Ответ:

-4

Объяснение:

$(2 \cot270 - 2 \cos60+ {( \sin60 )}^{2}) {}^{ - 1} = \frac{1}{ 2 \cot(360 - 90) - 2 \times 0.5 + {( \frac{ \sqrt{3} }{2}) }^{2} } = \frac{1}{2 \cot90 - 1 + 0.75} = \frac{1}{2 \times 0 - 0.25} = \frac{1 }{ - 0.25} = - \frac{ 1 }{ \frac{1}{4} } = - 4$