Question

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Answer 1

Объяснение:

$\frac{x^3-64x}{2x+16}=\frac{3x^2-24x}{y}\\ y=\frac{3x*(x-8)*2*(x+8)}{x*(x^2-64)} =\frac{6x*(x^2-64)}{x*(x^2-64)} =6.\\ y=6.$

Ответ:  y=6.