Question

3x². 15x^5
-----. : --------
16-y². 4+y​

Answer 1

Объяснение:

$\frac{3x^{2}}{16-y^{2} }:\frac{15x^{5}}{4+y} = \frac{3x^{2}}{(4-y)(4+y)}*\frac{4+y}{15x^{5}} = \frac{1}{5x^{3}(4-y)} = \frac{1}{20x^{3}-5x^{3}y}$