Question

Сократите дробь а) 9а/ 18а²-9а б) 5а-5б/25а²-25б²​

Answer 1

Ответ:

$a)\frac{9a}{18a^{2} -9a} =\frac{9a}{9a*(2a-1)} =\frac{1}{2a-1}$

$b)\frac{5a-5b}{25a^{2}-25b^{2} } =\frac{5*(a-b)}{25*(a^{2}-b^{2} ) } =\frac{5*(a-b)}{25*(a-b)(a+b)}=\frac{1}{5*(a+b)}=\frac{1}{5a+5b}$