Question

(3a-2)²- (3a+1)(a+5)

Answer 1

Ответ:

(3a-2)²-(3a+1)(a+5)

9a²-12a+4-(3a²+15a+a+5)

9a²-12a+4-(3a²+16a+5)

9a²-12a+4-3a²-16a-5

6a²-28a-1

Answer 2

${(3a - 2)}^{2} - (3a + 1)(a + 5) = {9a}^{2} - 12a + 4 - ( {3a}^{2} + 15a + a + 5) = {9a}^{2} - 12a + 4 - {3a}^{2} - 15a - a - 5 = {6a}^{2} - 28a - 1$