Question

Помогите пж решить 2 уровнения

Answer 1

Ответ:

1) $2 {x}^{2} + 9x - 5 = 0 \\ d = 81 + 4 \times 5 \times 2 \\ d = 121 = 11 \\ x = \frac{9 - 11}{4} = 1 \\ x = \frac{9 + 11}{4} = 5$

2) $x {}^{2} - 6x - 27 = 0 \\ x1 + x2 = - 6 \\ x1 \times x2 = - 27 \\ x1 = - 9 \\ x2 = 3$