Question

помогите пожалуйста!!!!!!!даю 50балов!!!!!!!!!!!​

Answer 1

$\left \{\begin{array}{l} \dfrac{2x+ 2,5y}{5} + \dfrac{4x-6y}{10} = -0,3 ~~ \big | \cdot 10  \\\\\\ \dfrac{-2x -y}{12} + \dfrac{0,5x + 0,25y}{2} = \dfrac{1}{24}   ~~ \big | \cdot 24   \end{array} \right. \Leftrightarrow  \\\\\\ \Leftrightarrow \left \{ \begin{array}{l}  4x + 5y  + 4x - 6y = -3 \\\\ -4x-2y +6x + 3y = 1   \end{array} \right. \Leftrightarrow$

$\Leftrightarrow \oplus \left \{ \begin{array}{l}  8x -y = -3 \\\\ 2x+y = 1 \end{array}  \right.\Leftrightarrow\\\\\\8x +2x + y - y = -2 \\\\ 10x = -2 \\\\ x= -0,2 \\\\ y = 1 -2x = 1,4$

$\mathbb{OTBET} : \left\{ \begin{array}{l} (\bold8)\cdot x - (\bold1)\cdot y = -3 \\\\ (\bold2)\cdot x + (1)\cdot y = 1 \end{array}$

Решение системы уравнений  : ( -0,2   ;  1,4 )