Question

помогите пожалуйста пж пж

Answer 1

$\displaystyle\bf\\1)\\\\\frac{x}{x-2} -\frac{x}{x+2}=\frac{x\cdot(x+2)-x\cdot(x-2)}{(x-2)(x+2)}=\frac{x^{2} +2x-x^{2} +2x}{(x-2)(x+2)} =\\\\\\=\frac{4x}{x^{2} -4} \\\\\\2)\\\\\frac{4x}{x^{2} -4} :\frac{8}{x^{2} -4} =\frac{4x}{x^{2} -4} \cdot\frac{x^{2} -4}{8} =\frac{x}{2} \\\\\\3)\\\\9x+\frac{x}{2} =9x+0,5x=9,5x\\\\Otvet: \ 9,5x$