Question

343 (3), 344(2)ОЧЕНЬ СРОЧНО

Answer 1

Номер 343 (3)
f(x) =(x-3)²×(x-1)²=f'(x) =d/dx((x-3)²×(x-1)²=f'(x) =d/dx(((x-3) ×(x-1)) ²)=f'(x) =d/dx((x²-x-3x+3)²)=f'(x) =d/dx((x²-4x+3) ²)=f'(x) =d/dg(g²) ×d/dx(x²-4x+3)=f'(x) =2g×(2x-4)=f'(x) =2(x²-4x+3)×(2x-4)=f'(x) =4x³-24x²+44x-24
Номер 344 (2)
f(x) =x²/x+1=f'(x) =d/dx(x²/x+1)=d/dx(x²) ×(x+1) - x²×d/dx(x+1)/(x+1)²=f'(x) =2x×(x+1)-x²×1/(x+1) ²=f'(x) =x²+2x/(x+1)²
Удачи!