Question

Помощь по математике пожалуйста

Answer 1

Ответ: 7/48

$- \frac{37}{16} + \frac{33}{28} \times 1 \frac{13}{22} + 3 \div 5 \frac{1}{7} = - \frac{37}{16} + \frac{33}{28} \times \frac{35}{22} + 3 \div \frac{36}{7} = - \frac{37}{16} + \frac{15}{8} + 3 \times \frac{7}{36} = \frac{ - 37 + 30}{16} + \frac{7}{12} = - \frac{7}{16} + \frac{7}{12} = \frac{ - 21 + 28}{48} = \frac{7}{48}$

Ответ: 1 7/8

$\frac{33}{28} \times 1 \frac{13}{22} = \frac{33}{28} \times \frac{35}{22} = \frac{15}{8} = 1 \frac{7}{8}$

Ответ: -1 5/12

$\frac{35}{36} \times ( \frac{1}{2} + \frac{5}{14} ) - \frac{5}{6} \div \frac{10}{27} = \frac{35}{36} \times \frac{7 + 5}{14} - \frac{5}{6} \times \frac{27}{10} = \frac{35}{36} \times \frac{12}{14} - \frac{27}{12} = \frac{35}{42} - \frac{27}{12} = \frac{70 - 189}{84} = - \frac{119}{84} = - 1 \frac{35}{84} = - 1 \frac{5}{12}$