Question

решите систему уравнений 2x+3y+z=8, x-y+2z=3, 3x+2y+z=9

Answer 1

$begin{cases} 2x+3y+z=8\x-y+2z=3\3x+2y+z=9 end{cases}$

 

$begin{cases} -2x-3y-z=-8\-x+y-2z=-3\3x+2y+z=9 end{cases}$

 

-2z=-2

z=1

 

$begin{cases} 2x+3y+1=8\x-y+2=3\3x+2y+1=9 end{cases}$

 

$begin{cases} 2x+3y=7\x-y=1\3x+2y=8 end{cases}$

 

$begin{cases} x=y\<var>2x+3x=7</var>\3x+2x=8 end{cases}$

 

$begin{cases} x=y\<var>5x=7</var>\5x=8 end{cases}$

 

$begin{cases} x=y\<var>x=7/5</var>\x=8/5 end{cases}$

нет решений