Question

розвяжіть систему рівнянь
2х - у = 3 , х^2 - 2ху + 3у^2 = 3

Answer 1

Ответ:вот

Объяснение:

Answer 2

Объяснение:

$\left \{ {{2x-y=3} \atop {x^2-2xy+3y^2=3}} \right. \ \ \ \ \left \{ {{y=2x-3} \atop {x^2-2xy+3y^2=3}} \right.\ \ \ \ \ \left \{ {{y=2x-3} \atop {x^2-2x*(2x-3)+3*(2x-3)^2=3}} \right. \\\left \{ {{y=2x-3} \atop {x^2-4x^2+6x+3*(4x^2-12x+9)-3=0}} \right. \ \ \ \ \ \left \{ {{y=2x-3} \atop {-3x^2+6x+12x^2-36x+27-3=0}} \right. \ \ \ \ \ \left \{ {{y=2x-3} \atop {9x^2-30x+24=0\ |:3}} \right.$

$\left \{ {{y=2x-3} \atop {3x^2-10x+8=0}} \right. \ \ \ \ \left \{ {{y=2x-3} \atop {D=4\ \ \ \ \sqrt{D}=2 }} \right. \ \ \ \ \left \{ {{y_1=-\frac{1}{3}\ \ \ \ y_2=1} \atop {x_1=\frac{4}{3} \ \ \ \ x_2=2}} \right. .$

Ответ: (4/3;-1/3),  (2;1).