Question

Решить диф уравнение

Answer 1

Ответ:

P = sin2x — 2cos(x+y)

dP/dy = 2 sin (x+y)

Q = -2cos(x+y)

dQ/dx = 2 sin(x+y) = dP/dy

интегрируя P по х

F = -1/2cos(2x) — 2 sin(x+y) + c(y)

F'(y) = — 2 cos(x+y) + c'(y) = Q = — 2cos(x+y)

=> c'(y) =c

F = -1/2cos(2x) — 2sin(x+y) + c = 0