Question

(0,2x+1)2+(0,2x+1)(1-0,2x)

Answer 1

Ответ:

$(0,2x+1)^{2} +(0,2x+1)(1-0,2x) = \\ ( \frac{1}{5} x + 1)^{2} + (1 + 0.2x) \times (1 - 0.2x) = \\ \frac{1}{25} {x}^{2} + \frac{2}{5} x + 1 + 1 - 0.2^{2} \times {x}^{2} = \\ \frac{1}{25} {x}^{2} + \frac{2}{5} x + 1 + 1 - ( \frac{1}{5} )^{2} \times {x}^{2} = \\ \frac{1}{25} {x}^{2} + \frac{2}{5} x + 1 + 1 - \frac{1}{25} {x}^{2} = \\ \frac{2}{5} x + 1 + 1 = \frac{2}{5} x + 2 = 0.4x + 2$

Answer 2

Ответ:

0,4х+2

Пошаговое объяснение:

(0,2x+1)²+(1+0,2х)(1-0,2x)=0,04х²+0,4х+1+1-0,04х²=0,4х+2