Question

помогите пожалуйста ​

Answer 1

$1) \: \frac{6 {x}^{3} }{8 {x}^{2} } = \frac{3x}{4} = \frac{3}{4} x \\ \frac{3}{4} x = \frac{3}{4} \times \frac{4}{3} = 1$

$2)\frac{5 {y}^{4} }{10 {y}^{2} } = \frac{ {y}^{2} }{2} = \frac{1}{2} {y}^{2} \\ \frac{1}{2} {y}^{2} = \frac{1}{2} \times {( - \frac{1}{2} )}^{2} = \frac{1}{2} \times \frac{1}{4} = \frac{1}{8}$

$3)\frac{14 {m} }{21{m}^{4} } = \frac{2}{3 {m}^{3} } \\ \frac{2}{3 {m}^{3} } = \frac{2}{3 \times {2}^{3} } = \frac{1}{3 \times 4} = \frac{1}{12}$

$4) \: \frac{a {b}^{2} }{ {a}^{3} b} = \frac{b}{ {a}^{2} } \\ \frac{b}{ {a}^{2} } = \frac{ - 5}{ {( - \frac{1}{3} )}^{2} } = \frac{ - 5}{ \frac{1}{9} } = - 5 \times 9 \\ = - 45$

Answer 2

Ответ:

Объяснение:

1)  6x^3/(8x^2)=3x/4 при х=4/3:

3x/4 = (3*4/3)/4 = 1;

2)  5y^4/10y^2=y^2/2; при у=-1/2:

у^2/2=(-1/2)^2/2=1/4:2=1/8;

3)  14m/(21m^4)=2/(3m^3)  при m=2:

2/(3*2^3)=2/24 = 1/12;

4)  ab^2/a^2b=b/a при b=-5  а=-1/3

b/a=-5/(-1/3)=15.