Question

arcsin√3/2 - arccos1 + arctg(-√3)/arcctg (-√3/3). Решите срочно очень надо

Answer 1

arcsin√3/2 = π/3
arccos1 = 0
arctg(-√3) = -π/3
arcctg (-√3/3) = -π/3
π/3-0+1 = π/3 +1