Question

найдите значение выражения ​

Answer 1

Ответ:

$7$.

Объяснение:

$\left \{ {{(x-3)^{2}-(x+2)^{2}=-3y} \atop {(y+1)^{2}-(y-3)^{2}=16x}} \right. \\\\\left \{ {{x^{2}-2\cdot x\cdot3+3^{2}-(x^{2}+2\cdot x\cdot2+2^{2})=-3y} \atop {y^{2}+2\cdot y\cdot1+1^{2}-(y^{2}-2\cdot y\cdot3+3^{2})=16x}} \right. \\\\\left \{ {{x^{2}-6x+9-(x^{2}+4x+4)=-3y} \atop {y^{2}+2y+1-(y^{2}-6y+9)=16x}} \right. \\\\\left \{ {{x^{2}-6x+9-x^{2}-4x-4=-3y} \atop {y^{2}+2y+1-y^{2}+6y-9=16x}} \right. \\\\\left \{ {{-10x+5=-3y} \atop {8y-8=16x}} \right.$
$\left \{ {{-10x+5=-3y} \atop {y-1=2x}} \right. \\\\\left \{ {{-10x+5=-3y} \atop {y=2x+1}} \right. \\\\-10x+5=-3\cdot(2x+1) \\-10x+5=-3\cdot2x-3\cdot1 \\-10x+5=-6x-3\\-10x+6x=-3-5\\-4x=-8\\x=2\\y=2\cdot2+1=4+1=5\\\\(x_0;y_0)=(2;5)\\x_0+y_0=2+5=7$