Question

-(ײ - 2) - 0,3+7×+(ײ-0,2×) = 0​

Answer 1

Ответ: -0,25

$- ( {x}^{2} - 2) - 0.3 + 7x + ( {x}^{2} - 0.2x) = 0 \\ - {x}^{2} + 2 - 0.3 + 7x + {x}^{2} - 0.2x = 0 \\ 6.8x + 1.7 = 0 \\ 6.8x = - 1.7 \\ x = - 0.25$