Question

Даю 100 бл.
Розкрийте дужки
2•(x+y)
-5•(2-a)
-8•(-4+a)
-3•(-8-y)
2a(4+b)
10b(3a+4c)
-2•(x+y-z)

Answer 1

2*(х+у)=2х+2у
-5*(2-а)=-10+5а
-8*(-4+а)=32-8а
-3*(-8-у)=24+3у
2а(4+b)=8a+2ab
10b(3a+4c)=30ab+40bc
-2*(x+y-z)=-2x-2y+2z

Answer 2

$2(x + y) = 2x + 2y \\ - 5(2 - a) = - 10 + 5a \\ - 8( - 4 + a) = 32 - 8a \\ - 3( - 8 - y) = 24 + 3y \\ 2a(4 + b) = 8a + 2ab \\ 10b(3a + 4c) = 30ab + 40ac \\ - 2(x + y - z) = - 2x - 2y + 2z$