Question

Lim x стремится к бесконечности 2+x^2/3-5x^2

Answer 1

$\displaystyle\mathsf{ \lim_{x \to \infty} \frac{2+x^2}{3-5x^2} = \lim_{x \to \infty} \frac{x^2*(\frac{2}{x^2} +1)}{x^2*(\frac{3}{x^2}-5) } = \lim_{x \to \infty} \frac{\frac{2}{x^2} +1}{\frac{3}{x^2} -5} =-\frac{1}{5}. }$