Question

(4х-1.6)(8+х)=0 Помогите, пожалуйста ​

Answer 1

$\displaystyle\bf\\\Big(4x-1,6\Big)\Big(8+x\Big)=0\\\\\\\left[\begin{array}{ccc}4x-1,6=0\\8+x=0\end{array}\right\\\\\\\left[\begin{array}{ccc}4x=1,6\\x=-8\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =0,4\\x_{2} =-8\end{array}\right\\\\\\Otvet \ : \ 0,4 \ \ ; \ \ -8$