Question

упр 1.14 срочно 50баллов

Answer 1

Ответ:

Вычислить .

$1)\ \ 10^3-5^2:8+\Big(\dfrac{2}{3}\Big)^5\cdot 81=1000-25:8+\dfrac{32\cdot 3^4}{3^5}=1000-\dfrac{25}{8}+\dfrac{32}{3}=\\\\=\dfrac{1000\cdot 24-25\cdot 3+32\cdot 8}{24}=\dfrac{24181}{24}=\bf 1007\dfrac{13}{24}$  

$\displaystyle 2)\ \ 2,43\cdot \Big(\frac{1}{3}\Big)^3+6^2\, (2^5-28)=\frac{243}{100}\cdot \frac{1}{27} +36\cdot (32-28)=\frac{9}{100}+36\cdot 4=\\\\\\=0,09+144=\bf 144,09$

$\displaystyle 3)\ \ 9^3-15^2:16+\Big(\frac{3}{4}\Big)^3:\frac{27}{32}=729-\frac{225}{16}+\frac{3^3}{2^6}\cdot \frac{2^5}{3^3}=729-\frac{225}{16}+\frac{1}{2}=\\\\\\=\frac{729\cdot 16-225+16}{16}=\frac{11447}{16}=715\frac{7}{16}=\bf 715,4375$

$\displaystyle 4)\ \ (7^2-51)^3\cdot \frac{5}{9}+3,6:9^2=(49-51)^3\cdot \frac{5}{9}+\frac{36}{10}\cdot \frac{1}{81}=(-2)^3\cdot \frac{5}{9}+\frac{4}{10\cdot 9}=\\\\\\=\frac{-8\cdot 5}{9}+\frac{2}{5\cdot 9}=-\frac{40}{9}+\frac{2}{45}=\frac{-40\cdot 5+2}{45}=-\frac{198}{45}=-4\frac{2}{5}=\bf -4,4$