Question

{х²+у²=29
х²-у²=21


{х²-у²=8
х²+у²=10​

Answer 1

$\left \{ {{ {x}^{2} + {y}^{2} = 29 } \atop { {x}^{2} - {y}^{2} = 21}} \right. + \\ {2x}^{2} = 50 \\ {x}^{2} = 25 \\ x = ± \: 5 \\ \\ {5}^{2} + {y}^{2} = 29 \\ 25 + {y}^{2} = 29 \\ {y}^{2} = 4 \\ y = ± \: 2$$\left \{ {{ {x}^{2} - {y}^{2} = 8 } \atop { {x}^{2} + {y}^{2} = 10}} \right. + \\ {2x}^{2} = 18 \\ {x}^{2} = 9 \\ x = ± \: 3 \\ \\ {3}^{2} + {y}^{2} = 10 \\ 9 + {y}^{2} = 10 \\ {y}^{2} = 1 \\ y = ± \: 1$

Ответ: x=±3 ; y=±1