Question

решите неравенство
1)x-5<4(x-2)
2)4(3x+1)>6(3x-2)+7

Answer 1

$x - 5 < 4(x - 2) \\ x - 5 < 4x - 8 \\ x - 4x < - 8 + 5 \\ - 3x < - 3 \\ x > 1$

$4(3x + 1) > 6(3x - 2) + 7 \\ 12x + 4 > 18x - 12 + 7 \\ 12x - 18x > - 12 + 7 - 4 \\ - 6x > - 9 \\ x < 1.5$