Question

СРОЧНО!
Довести нерівність: 2(х-8) <x(x-6)​

Answer 1

2(x - 8) < x(x - 6)

2x - 16 < x2 - 6x

2x - 16 - x2 + 6x < 0

8x - 16 - x2 < 0

-(x2 - 8x + 16) < 0

-(x - 4)2 < 0

(x - 4)2 > 0

(x - 4)2 = 0

x=4

x € R\ (4)

Answer 2

2(x-8)<x(x - 6)

2x-16<x2-6x

2x-16-x2+6<0

8x-16-x2<0

-(x2-8x+16)<0

-(x-4)2<0

(x-4)2>0

(x-4)2=0

x=4

x€R\(4)

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