Question

помогите пожалуйста 45 баллов даб​

Answer 1

Решение и ответ:

$\[\sqrt {0,256 \cdot {{10}^7}} = \sqrt {\frac{{160}}{{625}} \cdot {{10}^7}} = \sqrt \displaystyle \frac{{16}}{{625}} \cdot 10 \cdot {{10}^7}} =\sqrt {\frac{{{4^2}}}{{{{25}^2}}} \cdot {{10}^8}} =\sqrt {{{\left( {\frac{4}{{25}}} \right)}^2} \cdot {{\left( {{{10}^4}} \right)}^2}} = \sqrt {{{\left( {\frac{4}{{25}}} \right)}^2}} \cdot \sqrt {{{\left( {{{10}^4}} \right)}^2}} =\frac{4}{{25}} \cdot {10^4}=1600$

$\displaystyle \sqrt {{{\left( {26\frac{{47}}{{64}}} \right)}^2} \cdot {2^{14}}}=\sqrt {{{\left( {26\frac{{47}}{{64}}} \right)}^2} \cdot {{\left( {{2^7}} \right)}^2}}=\sqrt {{{\left( {26\frac{{47}}{{64}}} \right)}^2}} \cdot \sqrt{{{\left( {{2^7}} \right)}^2}}= 26\frac{{47}}{{64}} \cdot {2^7} = \frac{{1711}}{{64}} \cdot 128=3422$

$\displaystyle \sqrt {25 \cdot 121 \cdot 10201}=\sqrt {{5^2} \cdot {{11}^2} \cdot {{101}^2}}=\sqrt {{5^2}} \cdot \sqrt {{{11}^2}} \cdot \sqrt {{{101}^2}}=5 \cdot 11 \cdot 101=5555$