Question

Решить с объяснением

Answer 1

$\displaystyle\bf\\\frac{3+8x-3x^{2} }{3x^{2} +10x+3} =\frac{-3x^{2}+8x+3 }{3x^{2} +10x+3}=\frac{-(3x^{2}-8x-3)}{3x^{2} +10x+3}=\\\\\\=\frac{-3\cdot(x-3)\cdot(x+\dfrac{1}{3}) }{3\cdot(x+3)\cdot(x+\dfrac{1}{3} )} =-\frac{x-3}{x+3}=\frac{3-x}{x+3}$