Question

помогите пожалуйста даю 30 баллов​

Answer 1

Решение и ответ:

$\displaystyle 7\frac{1}{3}\div2\frac{1}{2}=3\frac{2}{3}\div y$

$\displaystyle \frac{{22}}{3}\div\frac{5}{2}=\frac{{11}}{3}\div y$

$\displaystyle \frac{{22}}{3}\cdot\frac{2}{5}=\frac{{11}}{3}\cdot\frac{1}{y}$

$\displaystyle \frac{{44}}{{15}}=\frac{{11}}{{3y}}$

$\displaystyle 3y\cdot 44=11\cdot 15$

$\displaystyle 132 y=165$

$\displaystyle y=165\div 132$

$\displaystyle y=\frac{5}{4}=1\frac{1}{4}$

$\displaystyle 6\frac{1}{2}\div3\frac{3}{4}=3\frac{1}{4}\div y$

$\displaystyle \frac{{13}}{2}\div\frac{{15}}{4}=\frac{{13}}{4}\div y$

$\displaystyle \frac{{13}}{2}\cdot\frac{4}{{15}}=\frac{{13}}{4}\cdot\frac{1}{y}$

$\displaystyle \frac{{13}}{1}\cdot\frac{2}{{15}}=\frac{{13}}{{4y}}$

$\displaystyle \frac{{26}}{{15}}=\frac{{13}}{{4y}}$

$\displaystyle 4y\cdot 26=13\cdot 15$

$\displaystyle 104y=195$

$\displaystyle y=195\div 104$

$\displaystyle y=\frac{{15}}{8}=1\frac{7}{8}$