Question

Помогите прошу пожалуйста

Answer 1

Вроде бы так получится)

Answer 2

$\displaystyle\bf\\1)\\\\\Big(-\frac{3}{5} \Big)^{3} \cdot\Big(\frac{1}{2} \Big)^{4} =-\frac{27}{125} \cdot\frac{1}{16} =-\frac{27}{2000} =-0,0135\\\\2)\\\\\Big(\frac{1}{4} \Big)^{3} \cdot\Big(0,5\Big)^{3} =\frac{1}{64} \cdot 0,125=0,001953125\\\\3)\\\\\Big(\frac{1}{3} \Big)^{2} :\Big(1\frac{2}{3} \Big)^{2} =\frac{1}{9}:\Big(\frac{5}{3} \Big)^{2} =\frac{1}{9}:\frac{25}{9} =\frac{1}{9} \cdot\frac{9}{25} =\frac{1}{25} =0,04\\\\4)$

$\displaystyle\bf\\\Big(2\frac{1}{2} \Big)^{2} :\Big(1,3\Big)^{2} =\Big(\frac{5}{2}\Big)^{2} :\Big(\frac{13}{10} \Big)^{2} =\frac{25}{4} :\frac{169}{100} =\frac{25}{4} \cdot\frac{100}{169} = \frac{625}{169} =3\frac{118}{169}$