Question

Знайти суму(різницю) дробів:

ДАМ 50 БАЛОВ ​

Answer 1

Пошаговое объяснение:

а)

4d/7c - 3p/7c = (4d - 3p)/7c

б)

(с + 6)/14 + (8 - с)/14 = (6 + с + 8 - с)/14 = 14/14 = 1

в)

9d/6x - 3d/6x = (9d - 3d)/6x = 6d/6x = d/x

г)

b²/(b - 3) - 9/(b - 3) = (b² - 9)/(b - 3) =

(b-3)(b+3)/(b-3) = (b + 3)/1 = b + 3

д)

81/(9 - к) - к²/(9 - к) = (81 - к²)/(9 - к) =

(9-к)(9+к)/(9 - к) = (9 + к)/1 = 9 + к

е)

10d/(2d - m) + 5m/(m - 2d) =

10d/(2d - m) + 5m/-(2d - m) =

10d/(2d - m) - 5m/(2d - m) =

(10d - 5m)/(2d - m) = 5(2d - m)/(2d - m) =

5/1 = 5

Answer 2

Ответ:

Пошаговое объяснение:

а)  4d/7c - 3p/7c = (4d - 3p)/7c

б) (с + 6)/14 + (8 - с)/14 = (6 + с + 8 - с)/14 = 1

в) 9d/6x - 3d/6x = (9d - 3d)/6x = 6d/6x = d/x

г) b²/(b - 3) - 9/(b - 3) = (b² - 9)/(b - 3) = (b-3)*(b+3)/(b-3) = b + 3

д) 81/(9 - к) - к²/(9 - к) = (81 - к²)/(9 - к) = (9-к)*(9+к)/(9 - к)= 9 + к

е) 10d/(2d - m) + 5m/(m - 2d) = 10d/(2d - m) + 5m/-(2d - m) =

=10d/(2d - m) - 5m/(2d - m) = (10d - 5m)/(2d - m) = 5(2d - m)/(2d - m) =5