Question

треба розв'язання, чекаю на допомогу​

Answer 1

$1. \: \: \: \: \: 4 \times 1 \frac{1}{2} + 1 \frac{23}{25} \div \frac{3}{20} = 4 \times \frac{3}{2} + \frac{48}{25} \times \frac{20}{3} = 2 \times 3 + \frac{16 \times 4}{5} = 6 + \frac{64}{5} = \frac{30 + 64}{5} = \frac{94}{5} = 18 \frac{4}{5}$

$1 \: \: \: - \: \: \: Г$

$2. \: \: \: \: \: 4 \div 1 \frac{1}{2} + 2 \frac{1}{3} \times 7 \frac{1}{7} = 4 \div \frac{3}{2} + \frac{7}{3} \times \frac{50}{7} = 4 \times \frac{2}{3} + \frac{50}{3} = \frac{8}{3} + \frac{50}{3} = \frac{58}{3} = 19 \frac{1}{3}$

$2 \: \: \: - \: \: \: Д$

$3. \: \: \: \: \: 8 \frac{12}{33} \times (4 \frac{1}{3} - 2 \frac{1}{2} ) = \frac{276}{33} \times ( \frac{13}{3} - \frac{5}{2} ) = \frac{276}{33} \times \frac{26 - 15}{6} = \frac{276}{33} \times \frac{11}{6} = \frac{46}{3} = 15 \frac{1}{3}$

$3 \: \: \: - \: \: \: A$

$4. \: \: \: \: \: (18 \frac{1}{4} + 2 \frac{1}{6} ) \div 1 \frac{1}{4} = ( \frac{73}{4} + \frac{13}{6} ) \div \frac{5}{4} = \frac{219 + 26}{12} \times \frac{4}{5} = \frac{245}{12} \times \frac{4}{5} = \frac{49}{3} = 16 \frac{1}{3}$

$4 \: \: \: - \: \: \: Б$